Question

prove that BD bisects angel B as well as angle D​

Answer 1

Answer:

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]

⇒AB=BC=CD=DA

⇒AC⊥BD

InΔABC

⇒AB=BC

⇒∴∠CAB=∠ACB

⇒AO=OC

∴∠ABO=∠CBO

andsimillarlyinΔADC

⇒AD=DC

⇒AO=OC

∴correspondingangleareequal

⇒∠DAC=∠DCA

and∠CDO=∠ADO

Hence,ACbisect∠Aand∠CandBDbisects∠Band∠D

Answer 2

GIVEN :-

• AD = CD
• BA = BC

TO PROVE :-

• ANGLE 1 = ANGLE 3
• ANGLE 2 = ANGLE 4

PROOF :-

IN TRIANGLE ADB AND CDB

• AD = CD [ GIVEN ]
• BA = BC [ GIVEN ]
• BD = BD [ COMMON ]

HENCE,

TRI. ADB CONGRUENT TO TRI. CDB ( SSS )

BY C•P•C•T

$\angle{1} = \angle{3} \\ \angle{2} = \angle{4}$