prove that BD=DC if AB=AC
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pratimManash11:
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given:-AB=AC
T.P.T:-BD=DC
proof:-we know that the tangent drawn from an external point of a circle are equal.
Therefore,AE=BE
and, AF=FC
FC=CD
BE=BD
now as given,AB=AC
AE+BE=AF+FC
AE+BD=AF+CD
BD=CD( AE=AF)
Hence proved.☺️☺️☺️☺️☺️☺️
T.P.T:-BD=DC
proof:-we know that the tangent drawn from an external point of a circle are equal.
Therefore,AE=BE
and, AF=FC
FC=CD
BE=BD
now as given,AB=AC
AE+BE=AF+FC
AE+BD=AF+CD
BD=CD( AE=AF)
Hence proved.☺️☺️☺️☺️☺️☺️
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