Question

Prove that bisectors of the angle of a parallelogram enclose a rectangle if it is given that adjacent sides of a parallelogram are unequal .... Plz help..... its very imporatnt

Answer 1

Let P. Q. R and S be the points of intersection of the bisectors Angle A & B, B & C, C & D, and D & A.

DS bisects ∠D
AS bisects ∠A
So,
∠DAS + ∠ADS= 1/2 ∠A + 1/2∠D
= 1/2 (∠A+∠D)
=1/2 x 180
=90 

and, ∠DAS + ∠ADS + ∠DSA = 180
90+ ∠DSA =180
∠DSA= 90
so, ∠PSR= 90
likewise ∠APB = ∠SPQ= ∠PQR= ∠SRQ= 90

PQRS is a quadrilateral 

Answer 2

Answer:

thank you for answering this question becoz even i was confused about this