Question

prove that by algebra
1 = 4
right ans get brainli do not spam and report question is right and complete

Answer 1

HELLO MATE
HERE IS YOUR ANSWER
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Assume that we have two variables aand b, and that: a = b

Multiply both sides by a to get: a2 = ab

Subtract b2 from both sides to get: a2- b2 = ab - b2

This is the tricky part: Factor the left side (using FOIL from algebra) to get (a+ b)(a - b) and factor out b from the right side to get b(a - b). If you're not sure how FOIL or factoring works, don't worry—you can check that this all works by multiplying everything out to see that it matches. The end result is that our equation has become: (a + b)(a - b) = b(a - b)

Since (a - b) appears on both sides, we can cancel it to get: a + b = b

Since a = b (that's the assumption we started with), we can substitute b in for a to get: b + b = b

Combining the two terms on the left gives us: 2b = b

=> $( {2b}^{2})$ = ${b}^{2}$

=> $\bold{4b}^{2} = \: {b}^{2}$
=> 4=1

proved...
$</b>$
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BY SHIVAM SHAURYA

Answer 2

I have many methods to prove this ...

METHOD 1 :

0 = 0

⇒ 2² - 2² = 2² - 2²

⇒ ( 2 + 2 )( 2 - 2 ) = 2 ( 2 - 2 )

Cancel 2 - 2

⇒ 2 + 2 = 2

⇒ 4 = 2

⇒ 2 = 1

Square both sides :

⇒ 4 = 1

Proved .

Another method :

1 - 1 = 4 - 4

⇒ 1 ( 1 - 1 ) = 4 ( 1 - 1 )

⇒ 1 = 4

However the mistakes are :

We cannot simply cancel 1 - 1 both sides .

It is because 1 - 1 = 0 .

Division by 0 is an error !

This is called fallacy.