Question

Prove that
By using any formula ​

Answer 1

Answer:

0

Step-by-step explanation:

theta = Θ

$\sqrt{2+\sqrt{2+\sqrt{2+2cos (theta)} } }=2 cos \frac{theta}{8}$

let the theta be 0

then

$\sqrt{2+\sqrt{2+\sqrt{2+2cos 0} } }=2 cos \frac{0}{8}$

$\sqrt{2+\sqrt{2+\sqrt{2+2(1)} } }=2 cos0$

$\sqrt{2+\sqrt{2+\sqrt{4} } }=2(1)$

$\sqrt{2+\sqrt{2+\sqrt{4} } }=2$

$\sqrt{2\sqrt{2+2} }=2$

$\sqrt{2\sqrt{4} }=2$

$\sqrt{2+2}=2$

$\sqrt{4} =2$

$2=2$

LHS = RHS

so (theta) or Θ =  0