Question

Prove that ∆CAB ~ ∆CDE

Answer 1

Answer:

In triangle CAB and CDE

Angle C=Angle C(Common in both triangles)

DE//AB

Angle A=Angle D=48

Angle E=Angle B

So, ∆CAB~∆CDE(AA similarity)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

If AB||DE

<DAB=<CDE

In triangle CAB and triangle CDE

1. <ACB=<DCE
2. <BAC=<EDC

By AA similarity

triangle CAB ~ triangle CDE