Question

Prove that centre of the circle circumscribing the rectangle ABCD is a point of intersection of its diagonals

Answer 1

diagonals of a rectangle are equal and are bisected at point of intersection so for a circle circumscribing it length of bisected diagonal wil act as radius and hence point of intersection of diagonal is centre

Answer 2

BD is the diagonal of ABCD
<BAD=90
Same AC is the diameter
<ABC=90
let AC&BD intersect at o
Diagonal of rectangle bisect each other
OA=OB=OC=OD
PROVE