Question

Prove that chords equidistant from the centre of a circle are equal in length.

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Answer 1

Answer:

Let in the given circle, AB and CD are two chords which are at equal distance from centre so OE = OFand OA = OC (Radius) ∠AEO = CFO = 90 degree By RHS, ΔAEO ≅ ΔAFO BY CPCT, AE = CF means AB = CD Proved

Answer 2

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