Question

prove that chrods of the same length in a circle are at the same distance from the center?​

Answer 1

Answer:

Step-by-step explanation:

Let AB =CD are two chords

We draw OM and ON perpendiculars from centre O to AB and CD

Also perpendiculars from centre to chords bisect the chords

Now AB=CD

So AM=BM=CN=ND

Now in the ΔOMB and Δ OND

OB=OD=r

∠M=∠N

MB=ND

So ΔOMB ≅ Δ OND

Thus OM=ON