Math, asked by rakeshyadavdandu, 11 months ago

Prove that
Ci) cos 48° sin 18° - sin 48° cos 18° =-1÷2
TI​

Answers

Answered by manasmohanty
1

LhS =cos 48° sin 18° - sin 48° cos 18°

Step-by-step explanation:

=sin(48-18).

=[sin(A-B)= sinA*cosB-sinA*cosB]

=sin30°

Hence LHS=RHS=1÷2

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