Question

Prove that :- Congruent chords of circle are equidistant from the centre of the

circle​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Given : A circle have two equal chords AB and  CD.

AB=CD and OM perpendicular to AB, ON  perpendicular to CD  

To Prove : OM=ON  

Proof : AB=CD (Given)  

∵ the perpendicular drawn from the centre of a circle to bisect the chord  

∴21​AB=21​CD

⇒BM=DN  

In △OMB and △OND  

∠OMB=∠OND=900 [Given]  

OB=OD [Radii of same circle]  

Side BM= Side DN [Proved above]  

∴△OMB≅△OND [By R.H.S.]  

∴OM=ON [By C.P.C.T]