prove that converse of Pythagoras theorem
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Explanation:
the Converse of Pythagoras Theorem states that in a right triangle if the square of one side is equal to the squares of other two sides then the angle opposite to the first side is the right angle
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hi mate,
Proof: Construct another triangle, △EGF, such as AC = EG = b and BC = FG = a.
In △EGF, by Pythagoras Theorem:
EF²= EG² + FG² = b² + a²…………(1)
In △ABC, by Pythagoras Theorem:
AB² = AC² + BC²= b² + a² …………(2)
From equation (1) and (2), we have;
EF² = AB²
EF = AB
⇒ △ ACB ≅ △EGF (By SSS postulate)
⇒ ∠G is right angle
Thus, △EGF is a right triangle.
Hence, we can say that the converse of Pythagorean theorem also holds.
Hence Proved.
i hope it helps you.
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