Prove that
cos 15° - sin 15° 1
cos15° + sin 15° =1/√3
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LHS = (cos15- sin15)/(cos15+sin15)
= [(cos15-sin15)(cos 15-sin15)]/
[(cos15+sin15)(cos 15-sin15)]
= (Cos15-sin15 )2/( cos²15 - sin² 15 )
= [cos²15+sin² 15-2sin15cos15]/cos(2x15)
= [1-sin (2x15 )]/ cos30
= (1-sin30) / cos30
= (1-1/2)/(√3/2)
= (1/2)/(√3/2)
= 1/√3
= RHS
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