Math, asked by ayush3142, 11 months ago

Prove that cos 18 sin 18 = √2 sin 27​

Answers

Answered by nosumittiwari3
1
Cos18- Sin18= cos18 - cos72= -2×sin(18+72)/2 × sin (18-72)/2 (using CosC-CosD) = -2 sin45×sin(-27) 2sin45sin27 (sin(-x)=-sinx) =√2×sin27
ayush3142: please explain again
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