prove that (cos^2 θ/1-sin θ)-(sin^2 θ/1-cos θ)=sin θ- cos θ
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Answer:
Here, we will use,
cos2θ+sin2θ=1
1.) L.H.S.=1−cos2θsin2θ
=cos2θ+sin2θ−cos2θsin2θ
=sin2θsin2θ
=1=R.H.S.
2.) L.H.S.=1−(cos2θ1+sinθ)
=1−(1−sin2θ1+sinθ)
=1−((1−sinθ)(1+sinθ)1+sinθ)
=1−1+sinθ
=sinθ=R.H.S.
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