Question

Prove that: cos 27°.tan 27°.tan 63°.cosec 63°=1​

Answer 1

As we know :-

1. cosec x = sec(90 - x)
2. tan x = cot (90 - x)
3. tan x ( cot x ) = 1
4. cos x ( sec x ) = 1

So now : Taking LHS

cos 27°.cot 63°.tan 63°.sec 27°

= ( cos 27°.sec 27° ).( cot 63°.tan 63° )

= 1

=> LHS = RHS

HENCE PROVED

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