Question

prove that cos^3A-Cos3A/Sin^3A+sin3A=tanA​

Answer 1

$\small\colorbox{lightyellow} {\text{ \bf♕ Brainliest answer }}$

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Question :-

$\\ \rm\text{ Prove that }\dfrac{ \cos^3A- \cos3A}{ \sin^3A+ \sin3A}= \tan A$

$\mathbb\red{ \tiny A \scriptsize \: N \small \:S \large \: W \Large \:E \huge \: R}$

Step-by-step explanation:

$\\ \rm\implies L.H.S=\frac{ \cos^3A- \cos3A}{ \sin^3A+ \sin3A}$

$\\ \rm\implies \frac{ \sin(A) }{ \cos(A) }$

$\\ \boxed{\color{red} \rm\implies \tan(A) }\rm=R.H.S$

Answer 2

Step-by-step explanation:

$\small\colorbox{lightyellow} {\text{ \bf♕ Brainliest answer }}$

$\rule{300pt}{0.1pt}$

Question :-

$\begin{gathered} \\ \rm\text{ Prove that }\dfrac{ \cos^3A- \cos3A}{ \sin^3A+ \sin3A}= \tan A\end{gathered}$

$\mathbb\color{darkcyan} \tiny A \scriptsize \: N \small \:S \large \: W \Large \:E \huge \: R$

Step-by-step explanation:

$\begin{gathered} \\ \rm\implies L.H.S=\frac{ \cos^3A- \cos3A}{ \sin^3A+ \sin3A}\end{gathered}$

$\begin{gathered} \\ \rm\implies \frac{ \sin(A) }{ \cos(A) } \end{gathered}$

$\begin{gathered} \\ \boxed{\color{red} \rm\implies \tan(A) }\rm=R.H.S\end{gathered}$