prove that cos 65 cos 25 -sin 65 sin 25=0
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cos65 cos25 - sin 65 sin 25 =0
cos (65-90) cos 25 - sin (65-25) sin25= 0
sin25 cos 25 - sin (65-25) sin25 =0
0=0
cos (65-90) cos 25 - sin (65-25) sin25= 0
sin25 cos 25 - sin (65-25) sin25 =0
0=0
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Answer:
- We know that cosA cosB-sinA sinB =cos(A+B)
- Applying this formula we get,
LHS:
Cos65 cos25-sin 65 sin 25=cos(65+25)
=cos(90)
=0
=RHS
hence proved
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