Question

prove that cos 65°+ 2sin 35° =√3 cos 25°​

Answer 1

Step-by-step explanation:

sin25° cos65° + cos25° sin65°

=(sin 25°) {cos(90°-25°)}+cos 25°{sin(90°-25)}

=(sin 25°)(sin 25°) + (cos 25°)(cos 25°)

= sin225° + cos225°

= 1 (As sin2A + cos2A = 1)

Answer 2

Answer:

Cos - sin = √2 sin

Cos = √2sin + sin

Cos = sin (√2 + 1)

Cos (√2 - 1) = sin (√2 + 1) (√2 - 1)

√2cos - cos = sin (2 - 1)

√2cos - cos = sin

Sin = √2cos - cos

Sin + cos = √2cos.

Step-by-step explanation:

mate thanks