prove that :cos 6x=1-2sin^2 3x
Answers
Answer:
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Step-by-step explanation:
Simplifying
cos(6x) = 1 + -2sin2(3x)
Remove parenthesis around (6x)
cos * 6x = 1 + -2sin2(3x)
Reorder the terms for easier multiplication:
6cos * x = 1 + -2sin2(3x)
Multiply cos * x
6cosx = 1 + -2sin2(3x)
Remove parenthesis around (3x)
6cosx = 1 + -2in2s * 3x
Reorder the terms for easier multiplication:
6cosx = 1 + -2 * 3in2s * x
Multiply -2 * 3
6cosx = 1 + -6in2s * x
Multiply in2s * x
6cosx = 1 + -6in2sx
Solving
6cosx = 1 + -6in2sx
Solving for variable 'c'.
Move all terms containing c to the left, all other terms to the right.
Divide each side by '6osx'.
c = 0.1666666667o-1s-1x-1 + -1in2o-1
Simplifying
c = 0.1666666667o-1s-1x-1 + -1in2o-1
Reorder the terms:
c = -1in2o-1 + 0.1666666667o-1s-1x-1
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