Math, asked by cat40, 1 year ago

prove that cos 70 degree by sin 20 degree +cos 55 degree into cos 45 degree by 15 degree into tan 25 degree into tan 65 degree into tan 85 degree is equals to 2


ntlaller07: not able to understand the question

Answers

Answered by proraider
1

Make the question more specific


sanju2005: very bad
cat40: why
cat40: cos 70°/sin20° + cos 55° ×cosec35°/tan5°×tan25°×tan65°×tan85°. =2
cat40: sorry
Answered by aquialaska
3

Answer:

To Prove:

\frac{cos\,70^{\circ}}{sin\,20^{\circ}}+\frac{cos\,55^{\circ}\times cosec\,45^{\circ}}{tan\,5^{\circ}\times tan\,25^{\circ}\times tan\,65^{\circ}\times tan\,85^{\circ}}=2

Consider,

LHS\,=\,\frac{cos\,70^{\circ}}{sin\,20^{\circ}}+\frac{cos\,55^{\circ}\times cosec\,45^{\circ}}{tan\,5^{\circ}\times tan\,25^{\circ}\times tan\,65^{\circ}\times tan\,85^{\circ}}

=\,\frac{cos\,(90-70)^{\circ}}{sin\,20^{\circ}}+\frac{cos\,(90-45)^{\circ}\times cosec\,45^{\circ}}{tan\,(90-85)^{\circ}\times tan\,(90-65)^{\circ}\times tan\,65^{\circ}\times tan\,85^{\circ}}

=\,\frac{sin\,70^{\circ}}{sin\,20^{\circ}}+\frac{sin\,45^{\circ}\times cosec\,45^{\circ}}{cot\,85^{\circ}\times cot\,65^{\circ}\times tan\,65^{\circ}\times tan\,85^{\circ}}

=\,\frac{1}{1}+\frac{1}{cot\,85^{\circ}\times tan\,85^{\circ}\times cot\,65^{\circ}\times tan\,65^{\circ}}

=\,\frac{1}{1}+\frac{1}{1\times1}

=\,1+1

=\,2

=\,RHS

Hence Proved

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