Question

prove that cos 90 - theta into sin 90 minus theta into cos theta minus sin theta into tan theta + cot theta equal to 1​

Answer 1

Answer:

$\cos(90 - x) \times \sin(90 - x) \times ( \cos(x) - \sin(x) )( \tan(x) + \cot(x) ) \\ \\ = \sin(x) \cos(x) \times ( \cos(x) - \sin(x) )( \frac{ \sin(x) }{ \cos(x) } - \frac{ \cos(x) }{ \sin(x) } ) \\ \\ = ( \cos(x) - \sin(x) )( \sin {}^{2} (x) - \cos {}^{2} (x) )$

It is not 1 , add photograph of clear question