Math, asked by BR17, 9 months ago

prove that : cos A/1+sin A+tan A=sec A​

Answers

Answered by Anonymous
17

Answer:

ANSWER

To prove:- cosA/ 1+sinA +tanA=secA

Proof:-

Taking l.H.S., we have

cosA/1+sinA +tanA

= cosA/1+sinA +sinA/cosA

= cos^2A+sinA(1+sinA)/cosA(1+sinA)

= cos^2 A+sin^2 A+sinA/cosA+sinA

= 1+sinA/cosA(1+sinA) (∵sin^2 A+cos^2 A=1)

= 1/cosA

=secA

= R.H.S.

Hence proved.

Step-by-step explanation:

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