Prove that
COS A/1 + sin A + tan A = sec A
Answers
Answered by
1
Answer:
secA
Step-by-step explanation:
= cosA/1+sinA + sinA/cosA
= cos²A+sinA(1+sinA)/ (1+sinA) (cosA)
= cos²A+sinA+sin²A/ (1+sinA) (cosA)
= 1+sinA/ (1+sinA) (cosA)
= 1/cosA
= secA
Hence proved
Answered by
1
Answer:
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