prove that Cos A by 1 + sin a + 1 + sin a by cos A is equals to 2 secant a
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Answered by
12
Answer:-
I assume the grouping is
cos/(1 + sin) + (1 + sin)/cos = 2 sec common denominator is cos(1 + sin)
[ cos · cos + (1 + sin)(1 + sin) ] / [cos(1 + sin)] = 2 sec
[ cos2 + sin2 + 2 sin + 1 ] / [cos(1 + sin)] = 2 sec
[ 1 + 2 sin + 1] / [cos(1 + sin)] = 2 sec
[ 2 sin + 2] / [cos(1 + sin)] = 2 sec
[ 2(sin + 1] / [cos(1 + sin)] = 2 sec
2 1/cos = 2 sec
2 sec = 2sec.
⚡Hope it will help you.⚡
Answered by
5
solution:
LHS.
cos a/1+sin a+1+sin a/cos a
cos²a+(1+sin a)²/(1+sin a) cos a
cos²a+1+2sin a+sin²a/(1+sin a)cos a
2+2sin a/(1+sin a)cos a
2(1+sin a)/cos a(1+sin a)
=2/cos a=2sec a=RHS.
hope ! i have helped u.
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