Question

Prove that Cos A minus sin A + 1 upon Cos A + sin A minus 1 is equal to sec a + tan A

Answer 1

Step-by-step explanation:

CosA - SinA + 1 /

CosA + SinA - 1

Divide by CosA in numerator and denominator

1 - TanA + SecA /

1 + TanA - SecA

Identity - 1 + Tan ^2 A = Sec ^2 A

Therefore- 1 = Sec ^2 A - Tan^2 A

Putting Sec^2 A - Tan ^2 A in place of 1 in numerator

Sec^2 A - Tan^2 A - TanA + SecA /

1 + TanA - SecA

Sec A + Tan A ( 1 + TanA - Sec A) /

1 + Tan A - Sec A

Therefore

Sec A + Tan A

Hence Proved.

Answer 2

Step-by-step explanation:

Ur answer is in the above pic