Question

Prove that: (cos A + sin A) (sec A + cosec A) = (2 + sec A cosec A​

Answer 1

Answer:

2+secAcosecA

Step-by-step explanation:

sinA+cosA)(secA+cosecA)

=(sinA+cosA){(1/cosA)+(1/sinA)}

={(sinA+CosA)(sinA+cosA)}/{sinA×cosA}

=(sinA+cosA)²/(sinA×cosA)

=(sin²A+cos²A+2sinAcosA)/(sinA×cosA)

=(1+2sinAcosA)/(sinA×cosA)

=2+secAcosecA

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