prove that (cos ec 0-sin 0)(sec 0-cos 0)=1/tan 0+ cot 0
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QUESTION⤵
prove that (cos ec 0-sin 0)(sec 0-cosl 0)=1/tan 0+ cot 0
ANSWER ⤵
considerd the provided expression
(csc ∅-sin∅) (∅sec-cos∅)= 1
tan∅ +cot∅
consider the Lhs.
=(csc∅-sin∅) (sec∅-cos∅)
=( 1. -sin∅)( 1. - cos∅
sin∅ cos∅
=(1-sin ²∅)=(1-cos²∅)
sin∅ cos∅
=(cos²∅) (sin²∅)
( sin∅). (cos∅)
=cos ∅=sin∅
consider right hand side
= 1.
(tan∅-cos∅)
1.
sin∅ +cos∅
cos∅ sin∅
=cos ∅-sin∅
sin²+cos²
=cos∅sin∅
LHS=RHS
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