prove that cos power 4A - cos squareA = sin power4 A - sin squareA
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Answer:
cos
4
A−cos
2
A=sin
4
A−sin
2
A
LHS.
=cos
2
A(1−cos
2
A)
=cos
2
Asin
2
A[∵sin
2
A+cos
2
A=1]
RHS
=sin
2
A(1−sin
2
A)
=sin
2
Acos
2
A[∵sin
2
A+cos
2
A=1]
=cos
2
Asin
2
A
LHS=RHS
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