Question

Prove that cosФ+(sin²Ф/cosФ)=secФ

Answer 1

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Answer 2

$<b>L.H.S.</b>$ = cosФ + ( sin²Ф / cosФ )

Taking L.C.M.

= ( cos²Ф + sin²Ф ) / cosФ

$<b><u>{ cos²A + sin²A = 1 }</b></u>$

= 1 / cosФ

$<b>R.H.S.</b>$ = secФ

= 1 / cosФ

[ As sec is a reciprocal of cos ]

•°•

L.H.S. = R.H.S.

Hence verified.