prove that (cos theta- 2cos^3 theta)/2 sin^3 theta- sin theta
please very fast
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Answered by
0
Answer:
Sin theta - 2 sin cube theta/2cos cube theta -cos theta
= sin theta(1-2sin sq theta)/cos theta(2 cos sq theta -1)
= sin theta( cos 2 theta)/cos theta(cos 2theta)
= sin theta/cos theta
= tan theta proved
Hope it helps
Step-by-step explanation:
pls mark brainiest
Answered by
20
Answer:
Sin theta - 2 sin cube theta/2cos cube theta -cos theta
= sin theta(1-2sin sq theta)/cos theta(2 cos sq theta -1)
= sin theta( cos 2 theta)/cos theta(cos 2theta)
= sin theta/cos theta
= tan theta proved
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