prove that cos theta minus sin theta + 1 by cos theta + sin theta minus 1 equal to cosec theta + cot theta
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Answer:
proof given below:
Explanation:
Taking conjugate of the denominator
1−cosΘ1+cosΘ=1−cosΘ1+cosΘ⋅1−cosΘ1−cosΘ
=(1−cosΘ)212−cos2Θ
We have sin2Θ+cos2Θ=1
so sin2Θ=1−cos2Θ
=(1−cosΘ)2sin2Θ
=(1−cosΘsinΘ)2
Seperating the fractions
=(1sinΘ−cosΘsinΘ)2
=(cscΘ−cotΘ)2
proof given below:
Explanation:
Taking conjugate of the denominator
1−cosΘ1+cosΘ=1−cosΘ1+cosΘ⋅1−cosΘ1−cosΘ
=(1−cosΘ)212−cos2Θ
We have sin2Θ+cos2Θ=1
so sin2Θ=1−cos2Θ
=(1−cosΘ)2sin2Θ
=(1−cosΘsinΘ)2
Seperating the fractions
=(1sinΘ−cosΘsinΘ)2
=(cscΘ−cotΘ)2
Anurag7798:
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