Question

Prove that:
[cos theta/sin(90 - theta)] + [sin theta/cos(90 - theta)] = 2

Answer 1

Answer:

Step-by-step explanation:

Cosθ/Sin(90-θ) + Sinθ/Cos(90-θ)

=> Cosθ/Cosθ + Sinθ/Sinθ  (∵ Sin(90-θ) = Cosθ; Cos(90-θ) = Sinθ)

=>  1 + 1

=> 2