Math, asked by hrushitad16, 2 months ago

prove that cos theta + sin cube theta by cos theta + sin theta + cos cube theta minus sin cube theta by cos theta minus sin theta equals to 2

Answers

Answered by farhaanaarif84

0

Answer:

sinθ−2sin

3

θ

=

cosθ(2cos

2

θ−1)

sinθ(1−2sin

2

θ)

=

cosθ.cos2θ

sinθ.cosθ

=

cosθ

sinθ

=tanθ.

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