Prove that cos theta-sin theta+1/cos theta+ sin theta-1= cosec theta+ cot theta
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1
Answer:
Giventhat,
cosθ+sinθ−1
cosθ−sinθ+1
=cosecθ+cotθ
Now,
DividebothN
r
andD
r
withsinθ
=
sinθ
cosθ+sinθ−1
sinθ
cosθ−sinθ+1
=
cotθ+1−cosecθ
cotθ−1+cosecθ
=
cotθ−cosecθ+1
cotθ+cosecθ−(cosec
2
θ−cot
2
θ)
=
cotθ−cosecθ+1
cotθ+cosecθ−cosec
2
θ+cot
2
θ
=
cotθ−cosecθ+1
cotθ+cosecθ(1−(cosec
2
θ−cot
2
θ))
=cotθ+cosecθ
HenceL.H.S=R.H.S
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Answered by
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Answer:
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