Prove that (cos x + cos y) 2 +(sin x + sin y) 2 =4cos 2 [(x-y)/2]
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LHS = cos2 x + cos2 y + 2 cos x cos y + sin2 x + sin2y + 2 sin x sin y
= 2 + 2 ( cos x cos y + sin x siny )
= 2 ( 1 + cos ( x - y ) )
= 2 * 2 cos2 ( x - y /2 )
= 4 cos2 ( x - y /2 ) = RHS
= 2 + 2 ( cos x cos y + sin x siny )
= 2 ( 1 + cos ( x - y ) )
= 2 * 2 cos2 ( x - y /2 )
= 4 cos2 ( x - y /2 ) = RHS
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