prove that cos(x+y)=cosx*cosy-sinx*siny
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Let us take a circle of radius one and let us take 2 points P and Q such that P is at an angle x and Q at an angle y
as shown in the diagram
Therefore, the co-ordinates of P and Q are P(cosx,sinx),Q(cosy,siny)
Now the distance between P and Q is:
(PQ) 2 =(cosx−cosy) 2 +(sinx−siny) 2=2−2(cosx.cosx+sinx.siny)
Now the distance between P and Q u\sin g \cos ine formula is
(PQ) 2 =1 2 +1 2 −2cos
(x−y)=2−2cos(x−y)
Comparing both we get
cos(x−y)=cos(x)cos(y)+sin(x)sin(y)
Substituting y with −y we get
cos(x+y)=cosxcosy−sinxsiny
Hope this'll help you.
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