Question

prove that cos0-si 0+1/ cos0+sin0+1 = 1+cos0/sin0​

Answer 1

Answer:

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

$(1 - cos∅ + sin∅)/(cos∅ + sin∅ - 1) = sin∅/cos∅</p><p>$

$L.H.S → (1 - cos∅ + sin∅)/(cos∅ + sin∅ - 1)</p><p>$

$→ (1 - cos∅ + sin∅)/(cos∅ + sin∅ - 1) × (cos∅ + sin∅ + 1)/(cos∅ + sin∅ + 1)</p><p>$

$→ (1 - cos∅ + sin∅)(cos∅ + sin∅ + 1)/[(cos∅ + sin∅)² - 1]</p><p>$

→ (cos∅ + sin∅ + 1 - cos²∅ - cos∅ sin∅ - cos∅ + sin∅ cos∅ + sin²∅ + sin∅)/(cos²∅ + sin²∅ + 2 sin∅ cos∅ - 1)

→ (1 - cos²∅ + sin²∅ + 2sin∅)/(1 + 2 sin∅ cos∅ - 1)

→ (1 - 1 + sin²∅ + sin²∅ + 2sin∅)/(2 sin∅ cos∅)

→ 2sin∅(sin∅ + 1)/2 sin∅ cos∅

→ (1 + sin∅)/cos∅

Proved

Hope it helps you

Answer 2

Answer:

iyred bnmax² + bx + c, then evaluate:

only correct answer

(i) α – β (ii) (1/α) – (1/β)

(iii) (

/α) + (1/β) – 2αβ (iv) α²β + αβ²

(v) α⁴ + β⁴ (vi) 1/(aα + b) + 1/(aβ + b)

(vii) β/(aα + b) + α/(aβ + b) (viii) a[(α²/β) + (β²/α)] + b[(α/β) + (β/α)]