Prove that cos10+cos 110+cos130 =0
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Answered by
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hello...
cos 10 + cos 110 + cos 130 = (cos 10 + cos 110) + cos 130
= 2 cos (110 + 10)/2 * cos (110 - 10)/2 + cos 130 {using cos C + cos D = 2 cos (C + D)/2 * cos (C - D)/2 }
= 2 cos 120/2 * cos 100/2 + cos (180 - 50) ( As 130 = 180 - 50)
= 2 cos 60 * cos 50 - cos 50 (Using cos (180 - A) = - cos A)
= 2 * 1/2 * cos 50 - cos 50 ( As cos 60 = 1/2)
= cos 50 - cos 50 = 0
I hope it help you....
please mark it as a brainieist answer....
cos 10 + cos 110 + cos 130 = (cos 10 + cos 110) + cos 130
= 2 cos (110 + 10)/2 * cos (110 - 10)/2 + cos 130 {using cos C + cos D = 2 cos (C + D)/2 * cos (C - D)/2 }
= 2 cos 120/2 * cos 100/2 + cos (180 - 50) ( As 130 = 180 - 50)
= 2 cos 60 * cos 50 - cos 50 (Using cos (180 - A) = - cos A)
= 2 * 1/2 * cos 50 - cos 50 ( As cos 60 = 1/2)
= cos 50 - cos 50 = 0
I hope it help you....
please mark it as a brainieist answer....
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