prove that cos²○+cos²(○+120°)+cos²(○-120°)=³/²
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Answer:
3/2
Step-by-step explanation:
Cos²θ + Cos²(θ+120) + Cos²(θ-120)
= 1 + Cos2θ/2 +1 + Cos2(θ+120) /2 + 1 + Cos2(θ-120) /2
3/2 + 1/2[Cos2θ + Cos(2θ+240)+Cos(2θ-240)]
= 3/2 + 1/2(Cos2θ + 2Cos2θCos240°)
= 3/2 + 1/2(Cos2θ + 2Cos2θCos(180+60))
= 3/2 + 1/2(Cos2θ + 2Cos2θCos(-60))
= 3/2+1/2(Cos2θ - Cos2θ)
= 3/2 + 0
= 3/2.
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