Prove that cos20.cos40.cos60.cos80=1/6
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cos 20 * cos40 *cos 60 *cos 80 = (1/2) cos 20 *cos 40 *cos 80 =
(1/2) 1/2(cos 120+cos 40) * cos 20 = (1/4) cos 20* (-1/2 + cos 40)
= (-1/8) cos 20 + (1/4) cos 20 * cos 40 =
(-1/8) cos 20 + (1/4)(1/2)(cos 60 + cos 20) =
(-1/8) cos 20 + (1/8) cos 60 + (1/8) cos 20 = (1/8)(1/2) = 1/16
(1/2) 1/2(cos 120+cos 40) * cos 20 = (1/4) cos 20* (-1/2 + cos 40)
= (-1/8) cos 20 + (1/4) cos 20 * cos 40 =
(-1/8) cos 20 + (1/4)(1/2)(cos 60 + cos 20) =
(-1/8) cos 20 + (1/8) cos 60 + (1/8) cos 20 = (1/8)(1/2) = 1/16
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DEAR STUDENT,
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
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