Math, asked by mohammedzaid200110, 1 year ago

Prove that
Cos20-cos40-cos80=0

Answers

Answered by Ramcharan
13

cos20^{o}-cos40^{o}-cos80^{o}\\cos20^{o}-(cos40^{o}+cos80^{o})\\cos20^{o}-(2cos((40+80)/2 )^{o}cos((80-40)/2 )^{o})\\cos20^{o}-(2cos60^{o}cos20^{o})\\cos20^{o}(1-2cos60^{o})\\cos20^{o}(1-2(\frac{1}{2}} )\\cos20^{o}(0)\\=0


Ramcharan: Hope it helps you...mark as brainliest if it did
mohammedzaid200110: Thank u
mohammedzaid200110: I have done it
mohammedzaid200110: But not getting upto mark answer
Ramcharan: i didnt understand?
Answered by garampallysuraj2005
1

Answer:

prove that cos20°-cos40°-cos80°=0

cos20°-cos40°-cos80°

Take '-' common

cos20°-(cos40°+cos80°)

cos20°(2cos40+80/2×cos40-80/2)

cos20°-(1×cos20°)

cos20°-cos20°=0

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