Prove that cos20 cos40° cos60° cos80° = 1/16
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Answered by
1
we multiply the ques with 2*sin20
now
{2sinx* cosx=sin2x}
LHS=(2*sin20*cos20)*cos40*cos60*cos80/2sin20
=(sin40*2*cos40)*cos60*cos80/4sin20
=(sin80*cos80*2)*cos60/8sin20
=sin160/16sin20
=sin(180-20)/16sin20
=sin20/16sin20
=1/16
(hence prove)
now
{2sinx* cosx=sin2x}
LHS=(2*sin20*cos20)*cos40*cos60*cos80/2sin20
=(sin40*2*cos40)*cos60*cos80/4sin20
=(sin80*cos80*2)*cos60/8sin20
=sin160/16sin20
=sin(180-20)/16sin20
=sin20/16sin20
=1/16
(hence prove)
Answered by
1
DEAR STUDENT,
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
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