Prove that cos20 cos40° cos60° cos80° = 1/16
Answers
Answered by
26
we multiply the ques with 2*sin20
now
2sinx* cosx=sin2x
so
lhs=(2*sin20*cos20)*cos40*cos60*cos80/2sin20
=(sin40*2*cos40)*cos60*cos80/4sin20
=(sin80*c0s80*2)*cos60/8sin20
=sin160/16sin20 (cos60=1/2)
=sin(180-20)/16sin20
=sin20/16sin20
=1/16
so
lhs=rhs
now
2sinx* cosx=sin2x
so
lhs=(2*sin20*cos20)*cos40*cos60*cos80/2sin20
=(sin40*2*cos40)*cos60*cos80/4sin20
=(sin80*c0s80*2)*cos60/8sin20
=sin160/16sin20 (cos60=1/2)
=sin(180-20)/16sin20
=sin20/16sin20
=1/16
so
lhs=rhs
Answered by
5
DEAR STUDENT,
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
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