prove that cos2A (1+tan2A)=1
Answers
Answered by
31
Hi,
LHS = cos² A ( 1 + tan² A )
= cos² A × sec² A [ since 1+ tan² A = sec²A]
= cos² A × 1/cos² A
= 1
= RHS
I hope this helps you.
:)
LHS = cos² A ( 1 + tan² A )
= cos² A × sec² A [ since 1+ tan² A = sec²A]
= cos² A × 1/cos² A
= 1
= RHS
I hope this helps you.
:)
Answered by
3
Answer:
1 is the correct answer
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