Prove that:cos2a-cos3a/sin3a+sin2a=tan(a/2)
Answers
Answered by
1
Step-by-step explanation:
-2Sin(5a/2)*Sin(-a/2) / 2Sin(5a/2)*Cos(a/2)
2Sin(5a/2)*Sin(a/2) / 2Sin(5a/2)*Cos(a/2)
Sin(a/2) / Cos(a/2)
tan(a/2)
hence proof
Answered by
1
Answer:
Open identity cos A - cosB in numerator
And open SinA +Sin B in denominator
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