Prove that Cos²a + sin²a = 1
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Step-by-step explanation:
Cos A = Base/Hypotenuse (B/H)
Sin A = Perpendicular/Hypotenuse (P/H)
By Pythagoras Theorem,
H^2 = P^2 + B^2 .......(1)
sin^2 A + cos^2 A
P^2/H^2 + B^2/H^2
(P^2 + B^2)/H^2
From (1),
H^2/H^2 = 1
Hence, Sin^2 A + Cos ^2 A = 1
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