prove that cos2A=sin3A
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cos2A=sin3A
we know that:sin=sin(90-A)=cosA and cos(90-A)=sinA
so,cos(90-2A)=sin2A = sin (90-3A)=cos3A
on dividing,we have
sin2A=sin3A
we know that:sin=sin(90-A)=cosA and cos(90-A)=sinA
so,cos(90-2A)=sin2A = sin (90-3A)=cos3A
on dividing,we have
sin2A=sin3A
alok8865:
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