Question

Prove that cos37°+sin37°÷cos37°-sin37°=Tan82°
$cos37°+sin37°÷cos37°-sin37°=Tan82°$

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Answer 1

Answer:

Step-by-step explanation:

ow let us consider the sides of the triangle as per the Pythagorean triplet.

Let us consider the right-angled triangle with sides as 3cm, 4cm and 5cm.

When the angle = 37° or 53°

cos A = base / hypotenuse

So, cos 53° = 3/5

cos 37° = 4/5

We know that

sin 90 – A = cos A

So cos 53° = sin 37 and cos 37° = sin 53°

Now

tan A = perpendicular / base

tan 37° = 3/4

tan 53° = 4/3

Answer

sin 37° = 3/5 = cos 53°

sin 53° = 4/5 = cos 37°

tan 37° = 3/4 = cot 53°

tan 53° = 4/3 = cot 37°