prove that cos3A= sin2A
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Cos3A= Sin2A ........ (i)
Cos3A= Cos (90-2A)
3A= 90-2A
5A= 90
A= 18
from (i)
Cos(3×18) = Sin (2×18)
Cos54= Sin36
0.5877= 0.5877 proved .
Cos3A= Cos (90-2A)
3A= 90-2A
5A= 90
A= 18
from (i)
Cos(3×18) = Sin (2×18)
Cos54= Sin36
0.5877= 0.5877 proved .
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